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प्रश्न
A set of three coils having resistances 10 Ω, 12 Ω, and 15 Ω are connected in parallel. This combination is connected in series with a series combination of three coils of the same resistances. Calculate the total resistance and current through the circuit, if a battery of emf 4.1 Volt is used for drawing current.
उत्तर
In the following figure shows the electrical network. For resistances, 10 Ω, 12 Ω and 15 Ω connected in parallel the equivalent resistance (RP) is given by,
`1/"R"_"p" = 1/10 + 1/12 + 1/15`
`= (6 + 5 + 4)/60`
`= 15/60 = 1/4`
∴ Rp = 4 Ω
For resistance Rp , 10 Ω, 12 Ω and 15 Ω connected in series, the equivalent resistance,
Rs = 4 + 10 + 12 + 15 = 41 Ω
Thus, the total resistance = Rs = 41 Ω
Now, V = lRs
∴ 4.1 = I × 41
∴ I = 0.1 A
The total resistance and current through the circuit are 41 Ω and 0.1 A respectively.
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