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A thin converging glass lens made of glass with refractive index 1.5 has a power of + 5.0 D. When this lens is immersed in a liquid of refractive index n, - Physics

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प्रश्न

A thin converging glass lens made of glass with refractive index 1.5 has a power of + 5.0 D. When this lens is immersed in a liquid of refractive index n, it acts as a divergent lens of focal length 100 cm. What must be the value of n?

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उत्तर

`"P"_"a"/"P"_"l" = ((mu_"g"/mu_"a" - 1))/((mu_"g"/mu_l - 1)) = 5/(- 100//100)` = - 5

`- 5 (mu_"g"/mu_l - 1) = mu_"g"/mu_"l" - 1`

`(1.5/mu_l - 1) = 1/5 (1.5 - 1)`

`mu_l = 1.5/0.9 = 5/3`

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पाठ 6: Ray Optics - Evaluation [पृष्ठ ५१]

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सामाचीर कलवी Physics - Volume 1 and 2 [English] Class 12 TN Board
पाठ 6 Ray Optics
Evaluation | Q 6. | पृष्ठ ५१
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