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Find the ratio of the intensities of lights with wavelengths 500 nm and 300 nm which undergo Rayleigh scattering. - Physics

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प्रश्न

Find the ratio of the intensities of lights with wavelengths 500 nm and 300 nm which undergo Rayleigh scattering.

संख्यात्मक

उत्तर

λ1 = 500

λ2 = 300 nm

`"I" prop 1/lambda^4`

`"I"_1/"I"_2 = ((lambda_2)/(lambda_1))^4`

`"I"_1/"I"_2 = (300/500)^4`

`"I"_1/"I"_2 = (3/5)^4`

`"I"_1/"I"_2 = 81/625`

`"I"_1: "I"_2 = 81 : 625`

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पाठ 6: Ray Optics - Evaluation [पृष्ठ ५१]

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सामाचीर कलवी Physics - Volume 1 and 2 [English] Class 12 TN Board
पाठ 6 Ray Optics
Evaluation | Q 10. | पृष्ठ ५१
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