Advertisements
Advertisements
Question
Find the ratio of the intensities of lights with wavelengths 500 nm and 300 nm which undergo Rayleigh scattering.
Solution
λ1 = 500
λ2 = 300 nm
`"I" prop 1/lambda^4`
`"I"_1/"I"_2 = ((lambda_2)/(lambda_1))^4`
`"I"_1/"I"_2 = (300/500)^4`
`"I"_1/"I"_2 = (3/5)^4`
`"I"_1/"I"_2 = 81/625`
`"I"_1: "I"_2 = 81 : 625`
APPEARS IN
RELATED QUESTIONS
An object is placed in front of a convex mirror of focal length of f and the maximum and minimum distance of an object from the mirror such that the image formed is real and magnified.
The radius of curvature of curved surface at a thin planoconvex lens is 10 cm and the refractive index is 1.5. If the plane surface is silvered, then the focal length will be.
What are primary focus and secondary focus of convex lens?
Arrive at lens equation from lens maker’s formula.
Derive the equation for effective focal length for lenses in contact.
Derive the equation for thin lens and obtain its magnification.
Derive the equation for effective focal length for lenses in out of contact.
A thin converging glass lens made of glass with refractive index 1.5 has a power of + 5.0 D. When this lens is immersed in a liquid of refractive index n, it acts as a divergent lens of focal length 100 cm. What must be the value of n?
If the distance D between an object and screen is greater than 4 times the focal length of a convex lens, then there are two positions of the lens for which images are formed on the screen. This method is called conjugate foci method. If d is the distance between the two positions of the lens, obtain the equation for a focal length of the convex lens.
A point object is placed at 20 cm from a thin plano-convex lens of focal length 15 cm whose plane surface is silvered. Locate the position and nature of the final image.
