Advertisements
Advertisements
प्रश्न
ABCD is a rectangle whose three vertices are A(4,0), C(4,3) and D(0,3). Find the length of one its diagonal.
उत्तर
The given vertices are B(4, 0), C(4, 3) and D(0, 3) Here, BD one of the diagonals So
BD =
= 5
Hence, the length of the diagonal is 5 units .
APPEARS IN
संबंधित प्रश्न
Let ABCD be a square of side 2a. Find the coordinates of the vertices of this square when A coincides with the origin and AB and AD are along OX and OY respectively.
Prove that the points (−2, 5), (0, 1) and (2, −3) are collinear.
Name the quadrilateral formed, if any, by the following points, and given reasons for your answers:
A(-3, 5) B(3, 1), C (0, 3), D(-1, -4)
Find a point on y-axis which is equidistant from the points (5, -2) and (-3, 2).
If the poin A(0,2) is equidistant form the points B (3, p) and C (p ,5) find the value of p. Also, find the length of AB.
Find the co-ordinates of the point equidistant from three given points A(5,3), B(5, -5) and C(1,- 5).
Show that the following points are the vertices of a square:
(i) A (3,2), B(0,5), C(-3,2) and D(0,-1)
The line segment joining the points A(3,−4) and B(1,2) is trisected at the points P(p,−2) and Q
If the point A(0,2) is equidistant from the points B(3,p) and C(p, 5), find p.
If
The co-ordinates of point A and B are 4 and -8 respectively. Find d(A, B).
ΔXYZ ∼ ΔPYR; In ΔXYZ, ∠Y = 60o, XY = 4.5 cm, YZ = 5.1 cm and XYPY =
Mark the correct alternative in each of the following:
The point of intersect of the coordinate axes is
Show that A (−3, 2), B (−5, −5), C (2,−3), and D (4, 4) are the vertices of a rhombus.
What is the area of the triangle formed by the points O (0, 0), A (6, 0) and B (0, 4)?
If points (a, 0), (0, b) and (1, 1) are collinear, then
If P is a point on x-axis such that its distance from the origin is 3 units, then the coordinates of a point Q on OY such that OP = OQ, are
Point (–10, 0) lies ______.
Abscissa of all the points on the x-axis is ______.
Point (3, 0) lies in the first quadrant.
