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प्रश्न
An aqueous solution of urea freezes at – 0.186°C, Kf for water = 1.86 K kg mo1–1, Kb for water = 0.512 K kg mo1–1. The boiling point of urea solution will be:
पर्याय
373.065 K
373.186 K
373.512 K
373.0512 K
उत्तर
373.0512
[0- (-0.186)] = 1.86 x m
`:. m = (0.186)/1.86 = 0.1`
`triangleT_b = K_b.m`
`:. triangleT_b = 0.512 xx 0.1`
= 0.0512
`T - T^@ = 0.0512`
`T = 0.0512 + T^@`
= 0.0512 + 373
= 373.01512 K
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