मराठी

In the Dehydration of Alcohols to Alkenes by Heating with Concentrated Sulphuric Acid, the Initiation Step Is: - Chemistry (Theory)

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प्रश्न

In the dehydration of alcohols to alkenes by heating with concentrated sulphuric acid, the initiation step is:

(1) formation of carbonation

(2) formation of an ester

(3) protonation of the alcohol molecule

(4) elimination of water

उत्तर

protonation of the alcohol molecule

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2017-2018 (March) Set 1

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संबंधित प्रश्‍न

What is metamerism? 


Write IUPAC name of the following compound:

\[\begin{array}{cc}
\ce{H3C - CH - CH2 - CH - CH - CH2 - CH3}\\
\phantom{}|\phantom{.............}|\phantom{......}|\phantom{.........}\\
\phantom{}\ce{OH}\phantom{..........}\ce{OH}\phantom{...}\ce{C2H5}\phantom{......}
\end{array}\]


Write the structures of the products when Butan-2-ol reacts with CrO3


Propanoic acid to ethylamine.


Resorcinol on distillation with zinc dust gives _________.


Write IUPAC names of the following


Isopropyl alcohol on oxidation forms:


\[\ce{Phenol ->[Zn, dust] 'X' ->[CH3Cl][Anhy. AlCl3] 'Y' ->[Alkaline][KMnO4] 'Z'}\]

The product ‘Z’ is:


Which of the following reagents can be used to oxidise primary alcohols to aldehydes?

(i) \[\ce{CrO3}\] in anhydrous medium.

(ii) \[\ce{KMnO4}\] in acidic medium.

(iii) Pyridinium chlorochromate.

(iv) Heat in the presence of Cu at 573 K.


Match the structures of the compounds given in Column I with the name of the compounds given in Column II.

  Column I Column II
(i) (a) Hydroquinone
(ii) (b) Phenetole
(iii) (c) Catechol
(iv) (d) o-Cresol
(v) (e) guinone
(vi) (f) Resorcinol
    (g) Anisole

Match the starting materials given in Column I with the products formed by these (Column II) in the reaction with HI.

  Column I   Column II
(i) CH3—O—CH3 (a)
(ii) \[\begin{array}{cc}
\ce{CH3}\phantom{..................}\\
\backslash\phantom{.............}\\
\ce{CH-O-CH3}\\
/\phantom{..............}\\
\ce{CH3}\phantom{..................}
\end{array}\]
(b) \[\begin{array}{cc}
\ce{CH3}\phantom{....}\\
|\phantom{.......}\\
\ce{CH3-C-I + CH3OH}\\
|\phantom{.......}\\
\ce{CH3}\phantom{....}
\end{array}\]
(iii) \[\begin{array}{cc}
\ce{CH3}\phantom{.}\\
|\phantom{....}\\
\ce{H3C-C-O-CH3}\\
|\phantom{....}\\
\ce{CH3}\phantom{..}
\end{array}\]
(c)
(iv) (d) CH3—OH + CH3—I
    (e) \[\begin{array}{cc}
\ce{CH3}\phantom{.....................}\\
\backslash\phantom{.................}\\
\ce{CH-OH + CH3I}\\
/\phantom{.................}\\
\ce{CH3}\phantom{.....................}
\end{array}\]
    (f) \[\begin{array}{cc}
\ce{CH3}\phantom{.....................}\\
\backslash\phantom{.................}\\
\ce{CH-I + CH3OH}\\
/\phantom{.................}\\
\ce{CH3}\phantom{.....................}
\end{array}\]
    (g) \[\begin{array}{cc}
\ce{CH3}\phantom{....}\\
|\phantom{.......}\\
\ce{CH3-C-OH + CH3I}\\
|\phantom{.......}\\
\ce{CH3}\phantom{....}
\end{array}\]

Assertion: Like bromination of benzene, bromination of phenol is also carried out in the presence of Lewis acid.

Reason: Lewis acid polarises the bromine molecule.


Assertion: Phenol forms 2, 4, 6 – tribromophenol on treatment with \[\ce{Br2}\] in carbon disulphide at 273 K.

Reason: Bromine polarises in carbon disulphide.


Explain why Lewis acid is not required in bromination of phenol?


Convert the following:

Ethyl alcohol into ethyl acetate


Identify A and B in the following:


How are the following conversions carried out?

Methyl magnesium bromide→2-Methylpropan-2-ol.


Draw structure of the following compound.

Prop-2-en-1-ol


Write IUPAC names of the following compounds: 

\[\begin{array}{cc}
\phantom{...............}\ce{CH3}\\
\phantom{.............}|\\
\ce{CH3 - CH - CH - C - CH3}\\
|\phantom{......}|\phantom{......}|\\
\phantom{...}\ce{CH3\phantom{...}OH\phantom{...}CH3}\\
\end{array}\] 


Write the IUPAC name of the following compound:

\[\begin{array}{cc}
\phantom{...............}\ce{CH3}\\
\phantom{.............}|\\
\ce{CH3 - CH - CH - C - CH3}\\
|\phantom{......}|\phantom{......}|\\
\phantom{...}\ce{CH3}\phantom{..}\ce{OH}\phantom{...}\ce{CH3}
\end{array}\]


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