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प्रश्न
Answer in one sentence:
Name the element that shows the simplest emission spectrum.
उत्तर
The element that shows the simplest emission spectrum is hydrogen.
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संबंधित प्रश्न
Answer in brief.
State the postulates of Bohr’s atomic model.
For the hydrogen atom, the minimum excitation energy ( of n =2) is ______
Using de Broglie’s hypothesis, obtain the mathematical form of Bohr’s second postulate.
The angular momentum of an electron in the 3rd Bohr orbit of a Hydrogen atom is 3.165 × 10-34 kg m2/s. Calculate Plank’s constant h.
Derive an expression for the radius of the nth Bohr orbit for the hydrogen atom.
Obtain an expression for wavenumber, when an electron jumps from a higher energy orbit to a lower energy orbit. Hence show that the shortest wavelength for the Balmar series is 4/RH.
Using the expression for the radius of orbit for the Hydrogen atom, show that the linear speed varies inversely to the principal quantum number n the angular speed varies inversely to the cube of principal quantum number n.
The radius of electron's second stationary orbit in Bohr's atom is R. The radius of the third orbit will be ______
When the electron in hydrogen atom jumps from fourth Bohr orbit to second Bohr orbit, one gets the ______.
For a certain atom when the system moves from 2E level to E, a photon of wavelength `lambda` is emitted. The wavelength of photon produced during its transition from `(4"E")/3` level to E is ____________.
How many moles of electrons are required for reduction of 9 moles of Cr3+ to Cr?
Taking the Bohr radius as a0= 53 pm, the radius of Li++ ion in its ground state, on the basis of Bohr's model, will be about ______.
The total energy of an electron in an atom in an orbit is -3.4 eV. Its kinetic and potential energies are, respectively ______.
In the nth orbit, the energy of an electron `"E"_"n"= -13.6/"n"^2"eV"` for hydrogen atom. The energy required to take the electron from first orbit to second orbit will be ____________.
If the speed of an electron of hydrogen atom in the ground state is 2.2 x 106 m/s, then its speed in the third excited state will be ______.
In Bohr model, speed of electron in nth orbit of hydrogen atom is ______. (b = Planck's constant, n = principal quantum number, ∈0 is the permittivity of free space, e = electronic charge)
The de-Broglie wavelength of an electron in 4th orbit is ______.
(r = radius of 1st orbit)
In any Bohr orbit of hydrogen atom, the ratio of K.E to P.E of revolving electron at a distance 'r' from the nucleus is ______.
Electron in Hydrogen atom first jumps from third excited state to second excited state and then from second excited state to first excited state. The ratio of the wavelengths λ1 : λ2 emitted in the two cases respectively is ______.
The third line of the Balmer series, in the emission spectrum of the hydrogen atom, is due to the transition from the ______.
The triply ionised beryllium (Be+++) has the same electron orbital radius as that of the ground state of the hydrogen atom. The energy state (n) of triply ionised beryllium is ______.
(Z for beryllium = 4)
The speed of an electron in ground state energy level is 2.6 × 106 ms-1, then its speed in third excited state will be ______.
Ultraviolet light of wavelength 300 nm and intensity 1.0 Wm−2 falls on the surface of a photosensitive material. If one percent of the incident photons produce photoelectrons, then the number of photoelectrons emitted from an area of 1.0 cm2 of the surface is nearly ______.
Calculate the energy of the electron in the ground state of the hydrogen atom. Express it in joule and in eV.
What is the origin of spectral lines? Obtain an expression for the wave number of a line in hydrogen spectrum.
Compute the shortest and the longest wavelength in the Lyman series of hydrogen atom.
