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प्रश्न
Answer the following question:
Find the distance of the origin from the line 12x + 5y + 78 = 0
उत्तर
Let p be the perpendicular distance of origin from the line 12x + 5y + 78 = 0.
Here, a = 12, b = 5, c = 78
∴ p = `|"c"/sqrt("a"^2 + "b"^2)|`
∴ p = `|78/sqrt(12^2 + 5^2)|`
= `|78/sqrt(144 + 25)|`
= `78/13`
= 6 units
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