Advertisements
Advertisements
प्रश्न
Answer the following question.
State the underlying principle of a cyclotron. Explain its working with the help of a schematic diagram. Obtain the expression for cyclotron frequency.
उत्तर
Cyclotron:
A cyclotron is a device used to accelerate charged particles to high energies. It was devised by Lawrence.
Principle:
Cyclotron works on the principle that a charged particle moving normal to the magnetic field experiences magnetic Lorentz force due to which the particle moves in a circular path.
Construction:
It consists of a hollow metal cylinder divided into two sections D1 and D2 called Dees, enclosed in an evacuated chamber. The Dees are kept separated and a source of ions is placed at the center in the gap between the Dees. They are placed between the pole pieces of a strong electromagnet. The magnetic field acts perpendicular to the plane of the Dees. The Dees are connected to a high-frequency oscillator.
Working:
When a positive ion of charge q and mass m is emitted from the source, it is accelerated towards the Dee having a negative potential at that instant of time. Due to the normal magnetic field, the ion experiences magnetic Lorentz force and moves in a circular path. By the time the ion arrives at the gap between the Dees, the polarity of the Dees gets reversed. Hence the particle is once again accelerated and moves into the other Dee with a greater velocity along a circle of greater radius. Thus the particle moves in a spiral path of increasing radius and when it comes near the edge, it is taken out with the help of a deflector plate (D.P). The particle with high energy is now allowed to hit the target T.
When the particle moves along a circle of radius r with a velocity v, the magnetic Lorentz force provides the necessary centripetal force.
`"Bqv" = ("mv"^2)/("r")`
`"v"/"r" = "Bq"/"m"` = constant ...(1)
The time taken to describe a semi-circle, `t = "πr"/"v" ......(2)`
Substituting equation (1) in (2),
`t = "πr"/"Bq"` .....(3)
It is clear from equation (3) that the time taken by the ion to describe a semi-circle is independent of (i) the radius (r) of the path and (ii) the velocity (v) of the particle.
Hence, the period of rotation `"T" = 2"t"`,
`"T" = (2"πm")/("Bq")` = constant ...(4)
So, in a uniform magnetic field, the ion traverses all the circles in exactly the same time. The frequency of rotation of the particle,
`ν = (1)/"T" = "Bq"/(2"πm")` .....(5)
If the high-frequency oscillator is adjusted to produce oscillations of frequency as given in equation (5), resonance occurs.
The cyclotron is used to accelerate protons, deuterons, and α - particles.
APPEARS IN
संबंधित प्रश्न
Draw a neat labelled diagram for the construction of 'cyclotron'
Which one of the following particles cannot be accelerated by a cyclotron?
(A) Electrons
(B) Protons
(C) Deuterons
(D) α- particles
In a cyclotron, magnetic field of 3·5Wb/m2 is used to accelerate protons. What should be the time interval in which the electric field between the Dees be reversed?
(Mass of proton = 1· 67 x 10-27Kg, Charge on proton =1·6x10-19c).
Deduce an expression for the frequency of revolution of a charged particle in a magnetic field and show that it is independent of velocity or energy of the particle.
Draw a schematic sketch of a cyclotron. Explain clearly the role of crossed electric and magnetic field in accelerating the charge. Hence derive the expression for the kinetic energy acquired by the particles.
Explain the principle and working of a cyclotron with the help of a schematic diagram. Write the expression for cyclotron frequency.
A cyclotron's oscillator frequency is 10 MHz. What should be the operating magnetic field for accelerating protons? If the radius of its 'dees' is 60 cm, calculate the kinetic energy (in MeV) of the proton beam produced by the accelerator.
A charged particle is moving in a cyclotron, what effect on the radius of path of this charged particle will occur when the frequency of the ratio frequency field is doubled?
Describe the motion of a charged particle in a cyclotron if the frequency of the radio frequency (rf) field were doubled.