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प्रश्न
Describe the motion of a charged particle in a cyclotron if the frequency of the radio frequency (rf) field were doubled.
उत्तर
The frequency va of the applied voltage (radio frequency) is adjusted so that the polarity of the dees is reversed at the same time that it takes the ions to complete one-half of the revolution. The requirement va = vc is called the resonance condition.
When the frequency of the radio frequency (rf) field was doubled, then the resonance condition are violated and the time period of the radio frequency (rf) field was halved. Therefore, the duration in which a particle completes half revolution inside the dees, radio frequency completes the cycle.
So, particles will accelerate and decelerate alternatively. So, the radius of path in the dees will remain the same.
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संबंधित प्रश्न
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(A) Electrons
(B) Protons
(C) Deuterons
(D) α- particles
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Answer the following question.
State the underlying principle of a cyclotron. Explain its working with the help of a schematic diagram. Obtain the expression for cyclotron frequency.
A charged particle is moving in a cyclotron, what effect on the radius of path of this charged particle will occur when the frequency of the ratio frequency field is doubled?
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The cyclotron was designed by ______
