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Question
Describe the motion of a charged particle in a cyclotron if the frequency of the radio frequency (rf) field were doubled.
Solution
The frequency va of the applied voltage (radio frequency) is adjusted so that the polarity of the dees is reversed at the same time that it takes the ions to complete one-half of the revolution. The requirement va = vc is called the resonance condition.
When the frequency of the radio frequency (rf) field was doubled, then the resonance condition are violated and the time period of the radio frequency (rf) field was halved. Therefore, the duration in which a particle completes half revolution inside the dees, radio frequency completes the cycle.
So, particles will accelerate and decelerate alternatively. So, the radius of path in the dees will remain the same.
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RELATED QUESTIONS
Which one of the following particles cannot be accelerated by a cyclotron?
(A) Electrons
(B) Protons
(C) Deuterons
(D) α- particles
State the underlying principle of a cyclotron. Write briefly how this machine is used to accelerate charged particles to high energies
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Give reason to justify your answer.
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A cyclotron is used to accelerate protons to a kinetic energy of 5 MeV. If the strength of magnetic field in the cyclotron is 2T, find the radius and the frequency needed for the applied alternating voltage of the cyclotron. (Given : Velocity of proton= `3xx10^7 m//s`)
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(a) there must be an electric field
(b) there must be a magnetic field
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Assertion: The frequency of circular motion of a charged particle in cyclotron is independent of the mass of the particle.
Reason: Greater the mass of the particle less will be the frequency of the particle.
Which of the following is not correct about cyclotron?
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