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प्रश्न
Arrange the following:
NaH, MgH2 and H2O in order of increasing reducing property.
उत्तर
Ionic hydrides are strong reducing agents. NaH can easily donate its electrons. Hence, it is most reducing in nature.
Both, MgH2 and H2O are covalent hydrides. H2O is less reducing than MgH2 since the bond dissociation energy of H2O is higher than MgH2.
Hence, the increasing order of the reducing property is H2O < MgH2 < NaH.
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संबंधित प्रश्न
Saline hydrides are known to react with water violently producing fire. Can CO2, a well-known fire extinguisher, be used in this case? Explain.
How can saline hydrides remove traces of water from organic compounds?
What do you expect the nature of hydrides is, if formed by elements of atomic numbers 15, 19, 23 and 44 with dihydrogen? Compare their behaviour towards the water.
Which of the following hydrides is electron-precise hydride?
Which of the following statements about hydrogen are correct?
(i) Hydrogen has three isotopes of which protium is the most common.
(ii) Hydrogen never acts as cation in ionic salts.
(iii) Hydrogen ion, \[\ce{H+}\], exists freely in solution.
(iv) Dihydrogen does not act as a reducing agent.
Which of the following statements is correct?
(i) Elements of group 15 form electron deficient hydrides.
(ii) All elements of group 14 form electron precise hydrides.
(iii) Electron precise hydrides have tetrahedral geometries.
(iv) Electron rich hydrides can act as Lewis acids.
NaH is an example of ______.
