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प्रश्न
Which of the following hydrides is electron-precise hydride?
पर्याय
\[\ce{B2H6}\]
\[\ce{NH3}\]
\[\ce{H2O}\]
\[\ce{CH4}\]
उत्तर
\[\ce{CH4}\]
Explanation:
\[\ce{CH4}\] is an electron precise hydride since there are exact number of electrons to form normal covalent bonds.
\[\begin{array}{cc}
\phantom{}\ce{H}\\
\phantom{}\ce{{x}}\\
\phantom{}\ce{\bullet}\\
\ce{H {x} \bullet C \bullet {x} H}\\
\phantom{}\ce{\bullet}\\
\phantom{}\ce{{x}}\\
\phantom{}\ce{H}
\end{array}\]
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(iii) Electron precise hydrides have tetrahedral geometries.
(iv) Electron rich hydrides can act as Lewis acids.
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