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प्रश्न
Assertion (A): Pent- 1- ene and pent- 2- ene are position isomers.
Reason (R): Position isomers differ in the position of functional group or a substituent.
पर्याय
Both A and R are correct and R is the correct explanation of A.
Both A and R are correct but R is not the correct explanation of A.
Both A and R are not correct.
A is not correct but R is correct.
उत्तर
Both A and R are correct and R is the correct explanation of A.
Explanation:
When two or more compounds differ in the position of substituent atom or functional group on the carbon skeleton, they are known as position isomers and this phenomenon is termed as position isomerism. Pent-2-ene and pent-l-ene are position isomers because they differ in the position of the double bond.
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संबंधित प्रश्न
What effect does branching of an alkane chain has on its boiling point?
Find out the type of isomerism exhibited by the following pair.
Which of the following is a functional isomer of pentan-2-ol?
The type of isomerism possible in 2-butene is ____________.
What is the relationship between the members of following pairs of structures? Are they structural or geometrical isomers or resonance contributors?
\[\begin{array}{cc}\ce{^+OH}\\||\\
\ce{H - C - OH}\end{array}\]
\[\begin{array}{cc}\ce{OH}\phantom{.}\\|\phantom{...}\\
\ce{H - C^+ - OH}\end{array}\]
In which of the following, functional group isomerism is not possible?
Which of the following pairs are not functional group isomers?
| I. | \[\begin{array}{cc} \phantom{.......................}\ce{O}\\ \phantom{.......................}||\\ \ce{CH3 - CH2 - CH2 - CH2 - C - H} \end{array}\] |
| II. | \[\begin{array}{cc} \phantom{.................}\ce{O}\\ \phantom{.................}||\\ \ce{CH3 - CH2 - CH2 - C - H} \end{array}\] |
| III. | \[\begin{array}{cc} \ce{CH3 - CH2 - C - CH2 - CH3}\\ \phantom{}||\\ \phantom{}\ce{O} \end{array}\] |
| IV. | \[\begin{array}{cc} \ce{CH3 - CH - CH2 - C - H}\\ \phantom{...}|\phantom{............}||\phantom{}\\ \phantom{...}\ce{CH3}\phantom{.........}\ce{O}\phantom{} \end{array}\] |
(i) II and III
(ii) II and IV
(iii) I and IV
(iv) I and II
Compounds with same molecular formula but differing in their structures are said to be structural isomers. What type of structural isomerism is shown by
CH3 – S – CH2 – CH2 – CH3
And
\[\begin{array}{cc}
\phantom{.....................}\ce{CH3}\\
\phantom{................}/\\
\phantom{}\ce{CH3 - S - CH}\\
\phantom{...............}\backslash\\
\phantom{....................}\ce{CH3}
\end{array}\]
Assertion (A): The compound cyclooctane has the following structural formula: 
It is cyclic and has conjugated 8π-electron system but it is not an aromatic compound.
Reason (R): (4n + 2)π electrons rule does not hold good and ring is not planar.
Which of the following does NOT exhibit geometrical isomerism?
The compound which shows metamerism is ______
How many structural isomers possible of the molecular formula C3H6O (excluding enol form)?
The number of acyclic structural isomers (including geometrical isomers) for pentene are ______.
Which of the following pairs of compounds are positional isomers?
The number of geometrical isomers from [Co(NH3)3(NO2)3] is ______.
The total number of possible isomers of the complex compound [CuII(NH3)4][PtIICl4] is ______.
Which of the following pairs of compounds is an example of position isomerism?
