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प्रश्न
Assign oxidation numbers to the underlined element in the following species:
H4P2O7
उत्तर
H4P2O7
| +1 | x | -2 |
| H4 | P2 | O7 |
Then, we have
4(+1) + 2(x) + 7(-2) = 0
⇒ 4 + 2x - 14 = 0
⇒ 2x = +10
⇒ x = + 5
Hence, the oxidation number of P is + 5.
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