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प्रश्न
Assign oxidation numbers to the underlined element in the following species:
NaH2PO4
उत्तर
Let the oxidation number of P be x.
We know that,
Oxidation number of Na = +1
Oxidation number of H = +1
Oxidation number of O = - 2
⇒
| +1 | +1 | x | -2 |
| Na | H2 | P | O4 |
Then, we have
1(+1) + 2(+1) + 1(x) + 4(-2) = 0
⇒ 1 + 2 + x - 8 = 0
⇒ x = + 5
Hence, the oxidation number of P is + 5.
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