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Calculate the Number of Photons Emitted per Second by a 10 W Sodium Vapour Lamp. Assume that 60% of the Consumed Energy is Converted into Light. - Physics

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प्रश्न

Calculate the number of photons emitted per second by a 10 W sodium vapour lamp. Assume that 60% of the consumed energy is converted into light. Wavelength of sodium light = 590 nm

(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)

बेरीज

उत्तर

Given:-

Power of the sodium vapour lamp, P = 10 W

Wavelength of sodium light, λ = 590 nm

Electric energy consumed by the bulb in one second = 10 J

Amount of energy converted into light = 60 %

∴ Energy converted into light = `60/100 xx 10 = 6 "J"`

Energy needed to emit a photon from the sodium atom,

`E^' = (hc)/λ`

`E^' = (6.63 xx 10^-34 xx 3 xx 10^8)/(590 xx 10^-9)`

`E^' = (6.63 xx 3)/590 xx 10^-17  "J"`

Number of photons emitted,

`n = 6/(((6.63 xx 3)/590) xx 10^-17)`

`n = (6 xx 590)/(6.63 xx 3) xx 10^17`

n = 1.77 × 1019

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Experimental Study of Photoelectric Effect
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पाठ 20: Photoelectric Effect and Wave-Particle Duality - Exercises [पृष्ठ ३६५]

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एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
पाठ 20 Photoelectric Effect and Wave-Particle Duality
Exercises | Q 4 | पृष्ठ ३६५

संबंधित प्रश्‍न

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(c) more energetic photons are emitted
(d) faster photons are emitted


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(d) electric charge of the photoelectrons is quantised


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(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


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Wavelength (nm):         350   400   450   500   550
Stopping potential (V): 1.45  1.00  0.66  0.38  0.16

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(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


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(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


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(a) Which physical parameter is kept constant for the three curves?

(b) Which is the highest frequency among v1, v2, and v3?


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