Advertisements
Advertisements
प्रश्न
Calculate the coefficient of cubical expansion of a zinc bar. Whose volume is increased 0.25 m3 from 0.3 m3 due to the change in its temperature of 50K?
उत्तर
Given: αv of Zn bar
Volume of zinc bar V0 = V1 = 0.3 m3
Change in volume ∆V = V2 – V1 = 0.25 – 0.30 = 0.05 m3
Change in temperature ∆T = 50K
Coefficient of cubical expansion αv = ?
∝v = `(Δ"v")/("v"_°Δ"T"` = `0.05/(0.3xx50)` = `0.05/15`
αv = 0.0033 K-1
APPEARS IN
संबंधित प्रश्न
At constant temperature, the effect of change of pressure on the volume of a gas was as given below:
|
Pressure in atmosphere |
Volume in liters |
|
0.20 |
112 |
|
0.25 |
89.2 |
|
0.40 |
56.25 |
|
0.60 |
37.40 |
|
0.80 |
28.10 |
|
1.00 |
22.4 |
(a) Plot the following graphs
- P vs V
- P vs 1/V
- PV vs P
Interpret each graph in terms of the law.
(b) Assuming that the pressure values given above are correct, find the correct measurement of the volume.
A steel cylinder of internal volume 20 litres is filled with hydrogen at 29 atmospheric pressure. If hydrogen is used to fill a balloon at 1.25 atmospheric pressure at the same temperature, what volume will the gas occupy?
A gas at 240 K is heated to 127°C. Find the percentage change in the volume of the gas (pressure remaining constant).
At 0°C and 760 mmHg pressure, a gas occupies a volume of 100 cm3. Kelvin temperature of the gas is increased by one-fifth and the pressure is increased one and a half times. Calculate the final volume of the gas.
22.4 litres of gas weighs 70 g at STP. Calculate the weight of the gas if it occupies a volume of 20 litres at 27°C and 700 mmHg of pressure.
State Boyle's Law.
Assuming temperature remaining constant calculate the pressure of the gas in the following:
The pressure of a gas having volume 380 lits. originally occupying 800 cm3 at 76 cm. pressure.
According to Boyle’s law, the shape of the graph between pressure and reciprocal of volume is _______.
State Boyle’s law
State-the law of volume
