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प्रश्न
Calculate the energy radiated in one minute by a blackbody of surface area 100 cm2 when it is maintained at 227°C. (Given: σ = 5.67 × 10-8 W/m2.K4)
उत्तर
Data: t = one minute = 60 s, A = 100 cm2
= 100 × 10-4 m2 = 10-2 m2, T = 273 + 227 = 500 K,
σ = 5.67 × 10-8 W/m2.K4
The energy radiated, Q = σAT4t
= (5.67 × 10-8)(10-2)(500)4(60) J
= (5.67)(625)(60)(10-2)J
= 2126 J
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