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प्रश्न
Choose the correct alternative:
Slope of the normal to the curve 2x2 + 3y2 = 5 at the point (1, 1) on it is
पर्याय
`-2/3`
`2/3`
`3/2`
`-3/2`
उत्तर
`3/2`
संबंधित प्रश्न
Find the derivative of the following function from first principle.
(x – 1) (x – 2)
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−x
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Choose the correct alternative.
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Fill in the blank:
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y = x2 + 4x at the point whose ordinate is -3.
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Find the equation of normal to the curve y = `sqrt(x - 3)` which is perpendicular to the line 6x + 3y – 4 = 0.
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The equation of tangent to the curve y = x2 + 4x + 1 at (– 1, – 2) is 2x – y = 0
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Find the equation of tangent and normal to the curve y = x2 + 5 where the tangent is parallel to the line 4x – y + 1 = 0.
