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महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

The slope of the tangent to the curve y = x3 – x2 – 1 at the point whose abscissa is – 2, is ______. - Mathematics and Statistics

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प्रश्न

The slope of the tangent to the curve y = x3 – x2 – 1 at the point whose abscissa is – 2, is ______.

पर्याय

  • – 8

  • 8

  • 16

  • – 16

MCQ
रिकाम्या जागा भरा

उत्तर

The slope of the tangent to the curve y = x3 – x2 – 1 at the point whose abscissa is – 2, is 16.

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पाठ 1.4: Applications of Derivatives - Q.1

संबंधित प्रश्‍न

Find the derivative of the following function from first principle.

(x – 1) (x – 2)


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−x


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(–x)–1


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The slope of tangent at any point (a, b) is called as _______.


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x = `1/"t",  "y" = "t" - 1/"t"`,  at t = 2


Find the equation of tangent and normal to the following curve.

y = x3 - x2 - 1 at the point whose abscissa is -2.


Find the equation of normal to the curve y = `sqrt(x - 3)` which is perpendicular to the line 6x + 3y – 4 = 0.


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Find the equations of tangent and normal to the curve y = 6 - x2 where the normal is parallel to the line x - 4y + 3 = 0


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