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प्रश्न
Construct a trapezium ABCD where AB || CD, AD = BC = 3.2 cm, AB = 6.4 cm and CD = 9.6 cm. Measure ∠B and ∠A.
[Hint: Difference of two parallel sides gives an equilateral triangle.]
उत्तर
Steps of construction:
Step I: Draw a line segment DC = 9.6 cm.
Step II: With D as centre, draw an angle measure 60°. Now, cut-off it with an arc 3.2 cm called point A.
Step III: Now, draw a parallel AB || CD.
Step IV: Talking C as centre, cut an arc B measure 3.2 cm on previous parallel line.
Step V: Draw a line segment BE = 3.2 cm from arc B.
Step VI: Join B to E and C.
Hence, ABCD is a required trapezium where ∠A = 120° and ∠B = 60°.
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