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प्रश्न
Construct a triangle XYZ with the given conditions.
An equilateral triangle of side 7.5 cm
उत्तर
Construction:
Step 1: Drawn a line. Marked X and Y on the line such that XY = 7.5 cm.
Step 2: With X as centre, drawn an arc of radius 7.5 cm above the line XY.
Step 3: With Y as centre, drawn an arc of radius 7.5 cm to intersect arc drawn in steps.
Marked the point of intersection as Z.
Step 4: Joined XZ and YZ.
Now XYZ in the required triangle.
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संबंधित प्रश्न
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