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प्रश्न
Construct an equilateral ∆ DEF whose one side is 5.5 cm. Construct an incircle to this triangle.
उत्तर
Steps of Construction :
(i) Draw a line segment BC = 5.5 cm.
(ii) With centres B and C and radius 5.5 cm each draw two arcs intersecting each other at A.
(iii) Join AB and AC.
(iv) Draw the perpendicular bisectors of ∠B and ∠C intersecting each other at I.
(v) From I, draw IL ⊥ BC
(vi) With centre I and radius IL, draw a circle which touches the sides of the Δ ABC internally.
This is the required incircle.
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संबंधित प्रश्न
Construct a ∆ABC such that:
CB = 6.5 cm, CA = 4.2 cm and BA = 51 cm
Construct a ∆ABC such that:
BC = 4 cm, AC = 5 cm and AB = 3.5 cm
Construct a ∆ ABC such that:
BC = 6 cm, AC = 5.7 cm and ∠ACB = 75°
Construct a ∆ PQR such that :
PQ = 6 cm, ∠Q = 60° and ∠P = 45°. Measure ∠R.
Construct an isosceles Δ ABC such that:
Base AB = 6.2 cm and base angle = 45°. Measure the other two sides of the triangle.
Construct an isosceles ∆ ABC such that:
One of the equal sides = 6 cm and vertex angle = 45°. Measure the base angles.
Construct an equilateral Δ ABC such that:
Each side is 6 cm.
Construct an isosceles ∆ PQR such that PQ = PR = 6.5 cm and ∠PQR = 75°. Using a ruler and compasses only constructs a circumcircle to this triangle.
Construct an isosceles ∆ MNP such that base MN = 5.8 cm, base angle MNP = 30°. Construct an incircle to this triangle and measure its radius.
Construct a ∆ PQR such that PQ = 6 cm, ∠QPR = 45° and angle PQR = 60°. Locate its incentre and then draw its incircle.
