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प्रश्न
Construct an isosceles ∆ MNP such that base MN = 5.8 cm, base angle MNP = 30°. Construct an incircle to this triangle and measure its radius.
उत्तर
Steps of Construction :
(i) Draw a line segment MN = 5.8 cm.
(ii) At M and N, draw two rays making an angle of 30° each which intersect each other at P.
(iii) Now draw the angle bisectors of ∠M and ∠N which intersects each other at I.
(iv) From I, draw the perpendicular IL on MN.
(v) With centre I and radius IL, draw a circle which touches the sides of the Δ PMN internally.
On measuring the required incircle and its radius is 0.6 cm.
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संबंधित प्रश्न
Construct a ∆ABC such that:
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AB = 7 cm, BC = 5 cm and ∠ABC = 60°
Construct a ∆ PQR such that :
PQ = 6 cm, ∠Q = 60° and ∠P = 45°. Measure ∠R.
Construct an isosceles Δ ABC such that:
Base AB = 6.2 cm and base angle = 45°. Measure the other two sides of the triangle.
Construct an isosceles ∆ ABC such that:
AB = AC = 6.5 cm and ∠A = 60°
Construct an equilateral Δ ABC such that:
AB = 5 cm. Draw the perpendicular bisectors of BC and AC. Let P be the point of intersection of these two bisectors. Measure PA, PB, and PC.
Construct an isosceles ∆ PQR such that PQ = PR = 6.5 cm and ∠PQR = 75°. Using a ruler and compasses only constructs a circumcircle to this triangle.
Construct a ∆ ABC such that AB = 6 cm, BC = 5.6 cm and CA = 6.5 cm. Inscribe a circle to this triangle and measure its radius.
Construct a ∆ PQR such that PQ = 6 cm, ∠QPR = 45° and angle PQR = 60°. Locate its incentre and then draw its incircle.
