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प्रश्न
Construct an equilateral Δ ABC such that:
AB = 5 cm. Draw the perpendicular bisectors of BC and AC. Let P be the point of intersection of these two bisectors. Measure PA, PB, and PC.
उत्तर
Steps of Construction :
(i) Draw a line segment AB = 5 cm.
(ii) With centres A and B and radius 5 cm each, draw two arcs intersecting each other at C.
(iii) Join AC and BC ∆ ABC is the required triangle.
(iv) Draw the perpendicular bisectors of sides AC and BC which intersect each other at P.
(v) Join PA, PB, and PC.
On measuring, each is 2.8 cm.
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