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प्रश्न
Construct an equilateral Δ ABC such that:
AB = 5 cm. Draw the perpendicular bisectors of BC and AC. Let P be the point of intersection of these two bisectors. Measure PA, PB, and PC.
उत्तर
Steps of Construction :
(i) Draw a line segment AB = 5 cm.
(ii) With centres A and B and radius 5 cm each, draw two arcs intersecting each other at C.
(iii) Join AC and BC ∆ ABC is the required triangle.
(iv) Draw the perpendicular bisectors of sides AC and BC which intersect each other at P.
(v) Join PA, PB, and PC.
On measuring, each is 2.8 cm.
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संबंधित प्रश्न
Construct a ∆ABC such that:
AB = 6 cm, BC = 4 cm and CA = 5.5 cm
Construct a ∆ABC such that:
CB = 6.5 cm, CA = 4.2 cm and BA = 51 cm
Construct a ∆ PQR such that:
QR = 4.4 cm, ∠R = 30° and ∠Q = 75°. Measure PQ and PR.
Construct a ∆ PQR such that:
PR = 5.8 cm, ∠P = 60° and ∠R = 45°. Measure ∠Q and verify it by calculations
Construct an isosceles Δ ABC such that:
Base AB = 6.2 cm and base angle = 45°. Measure the other two sides of the triangle.
Construct an isosceles Δ ABC such that:
Base AC = 5 cm and base angle = 75°. Measure the other two sides of the triangle.
Construct an isosceles ∆ ABC such that:
One of the equal sides = 6 cm and vertex angle = 45°. Measure the base angles.
Construct an equilateral Δ ABC such that:
Each side is 6 cm.
Construct an isosceles ∆ PQR such that PQ = PR = 6.5 cm and ∠PQR = 75°. Using a ruler and compasses only constructs a circumcircle to this triangle.
Construct an equilateral triangle ABC such that it's one side = 5.5 cm. Construct a circumcircle to this triangle.
