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प्रश्न
Construct a ∆ABC such that:
CB = 6.5 cm, CA = 4.2 cm and BA = 51 cm
उत्तर
Steps of Construction :
(i) Draw a line segment CB = 6.5 cm
(ii) With centre C and radius 4.2 cm draw an arc.
(iii) With centre B and radius 5.1 cm draw another arc intersecting the first arc at A.
(iv) Join AC and AB.
∆ ABC is the required triangle.
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संबंधित प्रश्न
Construct a ∆ABC such that:
AB = 6 cm, BC = 4 cm and CA = 5.5 cm
Construct a ∆ ABC such that:
AB = 6.5 cm, AC = 5.8 cm and ∠A = 45°
Construct a ∆ PQR such that :
PQ = 6 cm, ∠Q = 60° and ∠P = 45°. Measure ∠R.
Construct a ∆ PQR such that:
QR = 4.4 cm, ∠R = 30° and ∠Q = 75°. Measure PQ and PR.
Construct an isosceles Δ ABC such that:
Base AB = 6.2 cm and base angle = 45°. Measure the other two sides of the triangle.
Construct an isosceles ∆ ABC such that:
One of the equal sides = 6 cm and vertex angle = 45°. Measure the base angles.
Construct an equilateral Δ ABC such that:
AB = 5 cm. Draw the perpendicular bisectors of BC and AC. Let P be the point of intersection of these two bisectors. Measure PA, PB, and PC.
Construct a ∆ ABC such that AB = 6 cm, BC = 4.5 cm and AC = 5.5 cm. Construct a circumcircle of this triangle.
Construct an equilateral triangle ABC such that it's one side = 5.5 cm. Construct a circumcircle to this triangle.
Construct an isosceles ∆ MNP such that base MN = 5.8 cm, base angle MNP = 30°. Construct an incircle to this triangle and measure its radius.
