मराठी

Construct a Frequency Polygon Without Using a Histogram for the Following Frequency Distribution : Class Interval 1-10 11-20 21-30 31-40 41-50 Frequency 8 12 10 16 6 - Mathematics

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प्रश्न

Construct a frequency polygon without using a histogram for the following frequency distribution :

Class Interval  1-10 11-20 21-30 31-40 41-50
Frequency 8 12 10 16 6
बेरीज

उत्तर

Steps : 

1. Make the class intervals continuous by subtracting 0.5 from the lower limit of each class and add 0.5 to the upper limit of each class .

2. Find class mark by calculating the average of the class interval.

3. On the x-axis , take 1 cm as 5 units and plot class interval.

4. On the y-axis , take 1 cm as 5 units and plot frequency.

5. Plot the points on the graph. (5.5,8),(15.5,12),(25.5,10),(35.5,16),(45.5,6).

6. Mark two more midpoints of zero frequency on x-axis at the start and at the end.

7. Now connect the points using straight lines.

Class Interval Class Mark Frequency
0.5-10.5 = `(0.5+10.5)/2 = 5.5` 8
10.5-20.5 = `(10.5+20.5)/2 = 15.5` 12
20.5-30.5 = `(20.5 + 30.5)/2 = 25.5` 10
30.5-40.5 = `(30.5 + 40.5)/2 = 35.5` 16
40.5-50.5 = `(40.5 + 50.5)/2 = 45.5` 6

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पाठ 23: Graphical Representations - Exercise

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फ्रँक Mathematics - Part 2 [English] Class 10 ICSE
पाठ 23 Graphical Representations
Exercise | Q 3.03

संबंधित प्रश्‍न

Represent the following data by Histogram:

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Observe the following frequency polygon and write the answers of the questions below it.

  1. Which class has the maximum number of students?
  2. Write the classes having zero frequency.
  3. What is the class-mark of the class, having frequency of 50 students?
  4. Write the lower and upper class limits of the class whose class mark is 85.
  5. How many students are in the class 80-90?

Show the following data by a frequency polygon.
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Mark a frequency table with intervals as 800-810, 810-820 and so on, using tally marks. Also, draw a histogram and answer the following questions:
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