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प्रश्न
Construct an isosceles triangle with base 8 cm and altitude 4 cm. Construct another triangle whose sides are `2/3` times the corresponding sides of the isosceles triangle.
उत्तर
Steps of Construction
Step 1. Draw a line segment BC = 8 cm.
Step 2. Draw the perpendicular bisector XY of BC, cutting BC at D.
Step 3. With D as centre and radius 4 cm, draw an arc cutting XY at A.
Step 4. Join AB and AC. Here, ∆ABC is an isosceles whose base is 8 cm and altitude is 4 cm.
Step 5. Below BC, draw an acute angle ∠CBX.
Step 6. Along BX, mark three points B1, B2 and B3 such that BB1 = B1B2 = B2B3.
Step 7. Join CB3.
Step 8. From B2, draw B2C' || CB3 meeting BC at C'.
Step 9. From C', draw A'C' || AC meeting AB in A'.
Here, ∆A'BC' is the required triangle similar to ∆ABC such that each side of ∆A'BC' is `2/3` times the corresponding side of ∆ABC.
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