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Derive the expression for the torque on a current-carrying coil in a magnetic field. - Physics

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प्रश्न

Derive the expression for the torque on a current-carrying coil in a magnetic field.

दीर्घउत्तर

उत्तर

Consider a rectangular loop PQRS carrying current I is placed in a uniform magnetic field B. Let a and b be the length and breadth rectangular loop respectively. The unit vector n̂ normal to the plane of the loop makes an angle θ with the magnetic field.


Rectangular coil placed in a magnetic field

  1. The magnitude of the magnetic force acting on the current-carrying arm PQ is FPQ = IaBsin (π/2) = IaB.
  2. The magnitude of the force on the arm QR is FQR =IbBsin `(pi/2 - theta)` = lbB cos θ and its direction.
  3. The magnitude of the force on the arm RS is FRS =IaBsin (π/2) = IaB and its direction is downwards.
  4. The magnitude of the force acting on the arm SP is FSP = lbB`(pi/2 - theta)` = lbB cos θ and its direction.
  5. Since the forces FQR and FSP are equal, opposite, and collinear, they cancel each other. But the forces FPQ and FRS.

    Side view of current loop
  6. The magnitude of torque acting on the arm PQ about AB is τPQ = (1/2 sinθ) and points in the direction of AB. The magnitude of the torque acting on the arm. RS about AB is τRS = (b/2 sinθ) IaB and points also in the same direction AB.
  7. The total torque acting on the entire loop about an axis AB is given by
    `tau = ("b"/2 sin theta) "F"_"PQ" + ("b"/2 sin theta) "F"_"RS"`
    = Ia(bsinθ)B
    τ = IABsinθ along the direction B.
    In vector form,
    `vec tau= (vec"IA") xx vec"B"`.
  8. The above equation can also be written in terms of magnetic dipole moment.
    `vectau` = \[\overrightarrow{\mathrm{pm}}\] × \[\overrightarrow{\mathrm{B}}\] where \[\overrightarrow{\mathrm{pm}}\] = \[\overrightarrow{\mathrm{IA}}\]
  9. If there are N turns in the rectangular loop, the torque is given by
    τ = NIAB sinθ

Special cases:

  1. When θ =90° or the plane of the loop is parallel to the magnetic field, the torque on the current loop is maximum.
    τmax = IAB
  2. When θ = 0°/180° or the plane of the loop is perpendicular to the magnetic field, the torque on the current loop is zero.
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पाठ 3: Magnetism and magnetic effects of electric current - Evaluation [पृष्ठ १९२]

APPEARS IN

सामाचीर कलवी Physics - Volume 1 and 2 [English] Class 12 TN Board
पाठ 3 Magnetism and magnetic effects of electric current
Evaluation | Q III. 10. | पृष्ठ १९२

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