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प्रश्न
Diagram is given below shows velocity – time graph of car P and Q, starting from the same place and in the same direction. Calculate the Acceleration of car P.
उत्तर
Acceleration of car P = Slope of v.t. graph (OA) for car P.
= `"AB"/"OB"=35/10` = 3.5 ms−2
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संबंधित प्रश्न
Figure given below shows a velocity-time graph for a car starting from rest. The graph has three parts AB, BC and CD.
Which part of graph shows motion with uniform
(a) velocity (b) acceleration (c) retardation ?
Explain the following concept in your own words with everyday examples:
Acceleration
Draw velocity – time graph for the following situation:
When a body is moving with variable velocity, but uniform retardation.
A racing car is moving with a velocity of 50 m/s. On
applying brakes, it is uniformly retarded and comes to rest in 20 seconds. Calculate its acceleration.
Distinguish between uniformly and non-uniformly accelerated motions.
A car accelerates to a velocity of 30 m/s in 10 s and then decelerates for 20 s so that it stops. Draw a velocity-time graph to represent the motion and find:
Distance travelled
Assertion: The accelerated motion of an object may be due to change in magnitude of velocity or direction or both of them.
Reason: Acceleration can be produced only by change in magnitude of the velocity. It does not depend the direction.
The acceleration of the body that moves with a uniform velocity will be ______.
A car is being driven at a speed of 20ms-1 when brakes are applied to bring it to rest in 5 s. The deceleration produced in this case will be ______.
What is the difference between uniform acceleration and non–uniform acceleration?
