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प्रश्न
Diameter of the base of a cone is 10.5 cm and its slant height is 10 cm. Find its curved surface area.
`["Assume "pi=22/7]`
उत्तर
Radius (r) of the base of cone = `(10.5/2) cm` = 5.25 cm
Slant height (l) of cone = 10 cm
∴ The curved surface area of the cone = πrl
= `(22/7 xx 5.25 xx 10) cm^2`
= `(22 xx 0.75 xx 10) cm^2`
= 165 cm2
Therefore, the curved surface area of the cone is 165 cm2.
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`["Assume "pi=22/7]`
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