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प्रश्न
Distinguish between the given pairs of compounds using the test given within brackets:
Sodium nitrate and sodium sulphite (using dilute sulphuric acid).
उत्तर
Sodium nitrate on treatment with dilute sulphuric acid gives sodium bisulphate and nitric acid.
\[\ce{NaNO3 + H2SO4 -> NaHSO4 + HNO3}\]
Sodium sulphite treated with dilute sulphuric acid gives sodium sulphate and sulphur dioxide.
\[\ce{Na2SO3 + H2SO4 → Na2SO4 + H2O + SO2}\]
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संबंधित प्रश्न
How will you distinguish between dilute hydrochloric acid and dilute sulphuric acid using lead nitrate solution?
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Concentrated sulphuric acid is added to equal volumes of cold water.
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When solution of sulphur dioxide is exposed to air, it gets converted to sulphuric acid.
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On performing the flame test salt P produces a lilac coloured flame and its solution gives a white precipitate with silver nitrate solution. Which is soluble in ammonium hydroxide solution.
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