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Question
Distinguish between the given pairs of compounds using the test given within brackets:
Sodium nitrate and sodium sulphite (using dilute sulphuric acid).
Solution
Sodium nitrate on treatment with dilute sulphuric acid gives sodium bisulphate and nitric acid.
\[\ce{NaNO3 + H2SO4 -> NaHSO4 + HNO3}\]
Sodium sulphite treated with dilute sulphuric acid gives sodium sulphate and sulphur dioxide.
\[\ce{Na2SO3 + H2SO4 → Na2SO4 + H2O + SO2}\]
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