Advertisements
Advertisements
प्रश्न
Draw a graph of each of the following equations: 2(x - 5) = `(3)/(4)(y - 1)`
उत्तर
2(x - 5) = `(3)/(4)(y - 1)`
⇒ 8(x - 5) = 3(y - 1)
⇒ 8x - 40 = 3y - 3
⇒ 3y = 8x - 40 + 3
⇒ 3y = 8x - 37
y = `(8x - 37)/(3)`
When x = 2, = `(8(2) - 37)/(3)` = -7
When x = 5, y = `(8(5) - 37)/(3)` = 1
When x = -1, y = `(8(-1) - 37)/(3)` = -15
| x | 2 | 5 | -1 |
| y | -7 | 1 | -15 |
Plotting the points (2, -7), (5, 1) and (-1, -15), we get a line AB as shown in the figure.
APPEARS IN
संबंधित प्रश्न
Draw the graph for the linear equation given below:
y - 2 = 0
Draw the graph for the linear equation given below:
y = 0
Draw the graph for the linear equation given below:
y = `(2x)/(3) - 1`
Draw the graph for the each linear equation given below:
y = `(3x)/(2) + (2)/(3)`
Draw the graph for the linear equation given below:
2x - 3y = 4
Draw the graph for the equation given below:
2x - 5y = 10
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
y = x - 3
y = - x + 5
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
3x + 4y = 24
`x/(4) + y/(3) = 1`
The graph of 3x + 2y = 6 meets the x=axis at point P and the y-axis at point Q. Use the graphical method to find the co-ordinates of points P and Q.
Draw a graph of each of the following equations: y = `(5)/(2) xx + (2)/(5)`
