Advertisements
Advertisements
प्रश्न
Draw a graph of each of the following equations: y = `(3)/(5) x - 1`
उत्तर
y = `(3)/(5) x - 1`
When x = 5, y = `(3)/(5)(5) - 1` = 2
When x = -5, y = `(3)/(5)(-5) - 1` = -4
When x = 10, y = `(3)/(5)(10) - 1` = 5
| x | 5 | -5 | 10 |
| y | 2 | -4 | 5 |
Plotting the points (5, 2), (-5, -4) and (10, 5), we get a line AB as shown in the figure.
APPEARS IN
संबंधित प्रश्न
The following table gives production yield in kg per hectare of wheat of 100 farms of a village :
| Production yield (kg/hectare) : |
40−45 | 45−50 | 50−55 | 55−60 | 60−65 | 65−70 |
| Number of farms | 4 | 6 | 16 | 20 | 30 | 24 |
Change the distribution to a 'more than type' distribution, and draw its ogive.
Draw the graph for the linear equation given below:
x - 5 = 0
Draw the graph for the linear equation given below:
y - 2 = 0
Draw the graph for the linear equation given below:
x = 0
Draw the graph for the linear equation given below:
`(x - 1)/(3) - (y + 2)/(2) = 0`
Draw the graph for the equation given below:
`(1)/(2) x + (2)/(3) y = 5`.
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
2x - 3y = 6
`x/(2) + y/(3) = 1`
The graph of 3x + 2y = 6 meets the x=axis at point P and the y-axis at point Q. Use the graphical method to find the co-ordinates of points P and Q.
Draw the graph of equation `x/(4) + y/(5) = 1` Use the graph drawn to find:
(i) x1, the value of x, when y = 10
(ii) y1, the value of y, when x = 8.
Draw a graph of each of the following equations: x + 6y = 15
