Advertisements
Advertisements
Question
Draw a graph of each of the following equations: y = `(3)/(5) x - 1`
Solution
y = `(3)/(5) x - 1`
When x = 5, y = `(3)/(5)(5) - 1` = 2
When x = -5, y = `(3)/(5)(-5) - 1` = -4
When x = 10, y = `(3)/(5)(10) - 1` = 5
x | 5 | -5 | 10 |
y | 2 | -4 | 5 |
Plotting the points (5, 2), (-5, -4) and (10, 5), we get a line AB as shown in the figure.
APPEARS IN
RELATED QUESTIONS
Draw the graph of the equation given below.
2x + y = 1
Draw the graph for the linear equation given below:
x + 2y = 0
Draw the graph for the equation given below:
`(2x - 1)/(3) - (y - 2)/(5) = 0`
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
2x - 3y = 6
`x/(2) + y/(3) = 1`
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
3x + 4y = 24
`x/(4) + y/(3) = 1`
On the same graph paper, plot the graph of y = x - 2, y = 2x + 1 and y = 4 from x= - 4 to 3.
Use the graphical method to show that the straight lines given by the equations x + y = 2, x - 2y = 5 and `x/(3) + y = 0` pass through the same point.
Draw a graph of each of the following equations: x + 6y = 15
Draw a graph of each of the following equations: 3x - 2y = 6
Draw a graph of the equation 5x - 3y = 1. From the graph find the value of:
(i) x, when y = 8
(ii) y, when x = 2