Advertisements
Advertisements
प्रश्न
Draw a right angled Δ XYZ. Draw its medians and show their point of concurrence by G.
उत्तर
Steps of construction:
- Draw a right angled ∆XYZ.
- Draw the perpendicular bisector PQ of side YZ that intersect YZ at L.
- Join XL. XL is the median to the side YZ.
- Draw the perpendicular bisector TU of side ZX that intersect YZ at M.
- Join YM. YM is the median to side ZX.
- Draw the perpendicular bisector RS of side XY that intersect XY at N.
- Join ZN. ZN is the median to the side XY.
Hence, ∆XYZ is the required triangle in which medinas XL, YM and ZN to the sides YZ, ZX and XY respectively, intersect at G.
The point G is the centroid of ∆XYZ..
संबंधित प्रश्न
Draw rough sketch for the following:
In ΔABC, BE is a median.
Draw rough sketch for the following:
In ΔPQR, PQ and PR are altitudes of the triangle.
In Δ LMN, _____ is an altitude and _____ is a median. (write the names of appropriate segments.)
Draw an acute angled Δ PQR. Draw all of its altitudes. Name the point of concurrence as ‘O’.
Name the orthocentre of ∆PQR
The triangle ABC formed by AB = 5 cm, BC = 8 cm, AC = 4 cm is ______.
How many altitudes does a triangle have?
Which of the following figures will have it’s altitude outside the triangle?
The ______ triangle always has altitude outside itself.
Median is also called ______ in an equilateral triangle.
