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प्रश्न
Draw the graph of the equatio ` x / y + y /4 = 1` Also, find the area of the triangle formed by the
line and the co-ordinates axes.
उत्तर
` x / y + y /4 = 1`
⇒ 4x + 3y = 12
⇒ 4x = 12 - 3y
⇒ ` x = ( 12 - 3y) / 4`
Putting y = 0 in (1) , we get ` x = (12 - 3 × 0 ) /4` = 3
Putting y = - 4 in (2) We get ` x = (12 - 3× 4 )/ 4` = 0
Thus, we obtained the following table giving coordinates of two points on the line represents by the equation ` x/3 +y / 4` = 1
| x | 0 | 3 |
| y | 4 | 0 |
The graph of line ` x/3 +y / 4` = 1
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संबंधित प्रश्न
From the choices given below, choose the equation whose graphs are given in the given figures.
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(i) y = x
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(ii) y = x − 2
(iii) y = − x + 2
(iv) x + 2y = 6
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x - 5 = 0
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y + 5 = 0
Draw the graph for the following
y = `(3/2)x + 3`
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| x | 0 | − 1 | ||
| y | 0 | − 2 |
The graph of the linear equation 2x + 3y = 6 is a line which meets the x-axis at the point ______.
