23 ÷ 28 = `2^3/2^8 = 2^(3 - 8) = 2^-5 = 1/2^5`

Evaluate: 23 ÷ 28 - Mathematics

Evaluate: 2³ ÷ 2⁸

बेरीज

2³ ÷ 2⁸ = `2^3/2^8 = 2^(3 - 8) = 2^-5 = 1/2^5`

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Laws of Exponents (Through Observing Patterns to Arrive at Generalisation.)

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पाठ 5: Exponents (Including Laws of Exponents) - Exercise 5 (B)

पाठ 5 Exponents (Including Laws of Exponents)
Exercise 5 (B) | Q 2.2

Evaluate: (3⁰)⁶

Evaluate: (3⁵ x 4⁷ x 5⁸)⁰

Simplify, giving Solution with positive index

(- y²) (- y³)

Simplify, giving Solution with positive index

`2^"4a". 2^("3a") .2^(-"a")`

Simplify, giving Solution with positive index

(10²)³ (x⁸)¹²

Simplify, giving Solution with positive index:

(n²)² (- n²)³

Simplify, giving Solution with positive index

`(1/("4ab"^2"c"))^2 div (3/(2"a"^2"bc"^2))^4`

Simplify and express the Solution in the positive exponent form:

`("a"^-7 xx "b"^-7 xx "c"^5 xx "d"^4)/("a"^3 xx "b"^-5 xx "c"^-3 xx "d"^8)`

Evaluate: `(2^2)^0 + 2^-4 div 2^-6 + (1/2)^-3`

Evaluate: `5^"n" xx 25^("n" - 1) div (5^("n" -1) xx 25^("n" - 1))`