Advertisements
Advertisements
प्रश्न
Evaluate the following limits: `lim_(y -> 0)[(5y^3 + 8y^2)/(3y^4 - 16y^2)]`
उत्तर
`lim_(y -> 0)[(5y^3 + 8y^2)/(3y^4 - 16y^2)]`
= `lim_(y -> 0) (y^2 (5y + 8))/(y^2 (3y^2 - 16)`
= `lim_(y -> 0) (5y + 8)/(3y^2 - 16) ...[("As" y -> 0"," y ≠ 0),(therefore y^2 ≠ 0)]`
= `(5(0) + 8)/(3(0)^2 - 16`
= `8/(-16)`
= `-1/2`
APPEARS IN
संबंधित प्रश्न
Evaluate the following limits: `lim_(x -> 3) [1/(x - 3) - (9x)/(x^3 - 27)]`
Evaluate the following limits: `lim_("v" -> sqrt(2))[("v"^2 + "v"sqrt(2) - 4)/("v"^2 - 3"v"sqrt(2) + 4)]`
Evaluate the following Limits: `lim_(x -> 4)[(3 - sqrt(5 + x))/(1 - sqrt(5 - x))]`
Evaluate the following limit:
`lim_(z -> 2) [(z^2 - 5z + 6)/(z^2 - 4)]`
Evaluate the following limit :
`lim_(y -> 0)[(5y^3 + 8y^2)/(3y^4 - 16y^2)]`
Evaluate the following limit :
`lim_(x -> sqrt(2)) [(x^2 + xsqrt(2) - 4)/(x^2 - 3xsqrt(2) + 4)]`
Evaluate the following limit :
`lim_(x -> 1) [(x^4 - 3x^2 + 2)/(x^3 - 5x^2 + 3x + 1)]`
Evaluate the following limit :
`lim_(x -> 1) [(x + 2)/(x^2 - 5x + 4) + (x - 4)/(3(x^2 - 3x + 2))]`
Select the correct answer from the given alternatives.
`lim_(x -> 3) (1/(x^2 - 11x + 24) + 1/(x^2 - x - 6))` =
Evaluate the following
Limit: `lim_(x->1) [(x^3 - 1 )/ (x^2 + 5x -6)]`
Evaluate the following Limit.
`lim_(x->1)[(x^3 - 1)/(x^2 + 5x - 6)]`
Evaluate the following Limit.
`lim_(x->1)[(x^3 -1)/(x^2 +5x -6)]`
Evaluate the following limit:
`lim_(x->-2)[(x^7+x^5+160)/(x^3+8)]`
Evaluate the following limits:
`lim_(z→2)[( z^2 - 5 z + 6)/(z ^ 2 - 4)]`
Evaluate the following Limit.
`lim_(x -> 1)[(x^3 - 1)/(x^2 + 5x - 6)]`
Evaluate the following Limit:
`lim_(x->1)[(x^3-1)/(x^2+5x-6)]`
Evaluate the following limit:
`lim_(x->-2)[(x^7 + x^5 + 160)/(x^3 + 8)]`
Evaluate the following Limit.
`lim_(x->1)[(x^3 - 1)/(x^2 + 5x - 6)]`
