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Evaluate the (Vii) ( √ 3 + 1 ) 5 − ( √ 3 − 1 ) 5 - Mathematics

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प्रश्न

Evaluate the

(vii) \[\left( \sqrt{3} + 1 \right)^5 - \left( \sqrt{3} - 1 \right)^5\]

 

उत्तर

(vii) 

\[(\sqrt{3} + 1 )^5 - (\sqrt{3} - 1 )^5 \]
\[ = 2[ ^{5}{}{C}_1 \times (\sqrt{3} )^4 + ^{5}{}{C}_3 \times (\sqrt{3} )^2 +^{5}{}{C}_5 \times (\sqrt{3} )^0 ]\]
\[ = 2[5 \times 9 + 10 \times 3 + 1]\]
\[ = 2 \times 76 = 152\]

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Introduction of Binomial Theorem
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पाठ 18: Binomial Theorem - Exercise 18.1 [पृष्ठ ११]

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आरडी शर्मा Mathematics [English] Class 11
पाठ 18 Binomial Theorem
Exercise 18.1 | Q 2.07 | पृष्ठ ११

संबंधित प्रश्‍न

Using binomial theorem, write down the expansions  :

(iii)  \[\left( x - \frac{1}{x} \right)^6\]

\[= ^{5}{}{C}_0 (2x )^5 (3y )^0 +^{5}{}{C}_1 (2x )^4 (3y )^1 + ^{5}{}{C}_2 (2x )^3 (3y )^2 + ^{5}{}{C}_3 (2x )^2 (3y )^3 + ^{5}{}{C}_4 (2x )^1 (3y )^4 +^{5}{}{C}_5 (2x )^0 (3y )^5\]

\[= 32 x^5 + 5 \times 16 x^4 \times 3y + 10 \times 8 x^3 \times 9 y^2 + 10 \times 4 x^2 \times 27 y^3 + 5 \times 2x \times 81 y^4 + 243 y^5 \]
\[ = 32 x^5 + 240 x^4 y + 720 x^3 y^2 + 1080 x^2 y^3 + 810x y^4 + 243 y^5 \]

 

 


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