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Explain the Formation of a Chlorine Molecule on the Basis of Electronic Theory of Valency. - Science

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प्रश्न

 Explain the formation of a chlorine molecule on the basis of electronic theory of valency.

उत्तर

The atomic number of chlorine is 17 and its electronic configuration is 2, 8, 7. It needs one more electron to complete its octet. Chlorine gets this electron by sharing with another atom. So each chlorine atom shares one electron to form a chlorine molecule.

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पाठ 3: Metals and Non-metals - Exercise 2 [पृष्ठ १६८]

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लखमीर सिंह Chemistry (Science) [English] Class 10
पाठ 3 Metals and Non-metals
Exercise 2 | Q 23.2 | पृष्ठ १६८

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

State the type of bonding in the following molecule.

Water


Give one example of a molecule containing a double covalent bond


What is a covalent bond? 


How  buckminsterfullerene is it related to diamond and graphite?


Give two general properties of ionic compounds and two those of covalent compounds.


Draw the electron-dot structure of NHand state the type of bonding. 


Draw the electron-dot structure of N2 and state the type of bonding. 


What are the conditions necessary for the formation of covalent molecules?


State the type of bonding in the following molecule.

Methane


Complete the following:

In case of non-polar covalent bond, the covalent bond is formed in the ______ of atoms and shared electrons are ______ distributed. (corner, middle, equally, unequally)


State the type of bond formed when the combining atom has zero E.N. difference. 


What is the difference between a polar covalent compound and a non-polar covalent compound?


Name two carbon compounds used in day-to-day life.


Write an Explanation.

Alkyne


Write scientific reason.

Carbon has the property of forming many compounds.


Complete the following activity.

Write the names of the hydrocarbons for the following structural formula.

(isobutylene, cyclohexane, propene, cyclohexene, cyclopentane, benzene, propyne, isobutane, propane)

\[\begin{array}{cc}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\\\ce{H - C - C - C - H}\\
|\phantom{....}|\phantom{....}|\\\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}
\end{array}\]
 

An element A is soft and can be cut with a knife. This is very reactive to air and cannot be kept open in air. It reacts vigorously with water. Identify the element from the following


State the reasons, why carbon cannot

  1. Lose four electrons to form C4+ cation and
  2. Gain four electrons to form C4- anion.

How does carbon overcome this problem to form compounds?


Assertion (A): Melting point and boiling point of ethanol are lower than that of sodium chloride.

Reason (R): The forces of attraction between the molecules of ionic compounds are very strong. 


Carbon can neither form C4- cation nor C4 anion. Why?


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