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Explain optical activity of 2-chlorobutane - Chemistry

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प्रश्न

Explain optical activity of 2-chlorobutane

टीपा लिहा

उत्तर

  1. The property of a substance by which it rotates the plane of polarization of incident plane-polarized light is known as optical activity.
  2. 2-Chlorobutane has one chiral carbon atom and thus, exists as a pair of enantiomers which are non-superimposable mirror images of each other.
  3. These mirror images are referred to as optical isomers; which differ from each other in terms of a measurable property called optical activity. The structure of 2-chlorobutane and its mirror image can be represented as,
  4. Thus, 2-chlorobutane will show optical activity and in accordance with the direction of optical rotation, one isomer will be dextrorotatory, and the other will be laevorotatory.
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Optical Isomerism in Halogen Derivatives
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 10: Halogen Derivatives - Short Answer Questions (Type-Ⅰ)

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एससीईआरटी महाराष्ट्र Chemistry [English] 12 Standard HSC
पाठ 10 Halogen Derivatives
Short Answer Questions (Type-Ⅰ) | Q 4

संबंधित प्रश्‍न

Identify the chiral molecule from the following.


Explain optical isomerism in 2-chlorobutane.


For the isomeric dihalobenzenes, melting point of __________


Which of the following is NOT a chiral molecule?


While assigning R, S configuration, the correct order of priority of groups attached to chiral carbon atom is ______


Identify chiral molecule/s from the following.

a.

\[\begin{array}{cc}
\ce{CH3 - CH - CH2 - CH3}\\
|\phantom{.........}\\
\ce{OH}\phantom{.......}
\end{array}\]

b.

\[\begin{array}{cc}
\ce{CH3 - CH2 - CH - CH2 - CH3}\\
|\phantom{.}\\
\ce{Br}\phantom{.}
\end{array}\]

c.

\[\ce{CH3 - CH - CH2 - CH2Br}\]

d.

\[\begin{array}{cc}
\ce{CH3 - CH - CH2 - CH3}\\
|\phantom{.........}\\
\ce{CH3}\phantom{......}
\end{array}\]


Identify chiral molecule/s from the following.

a.

\[\begin{array}{cc}
\ce{CH3 - CH - CH2 - CH3}\\
|\phantom{.........}\\
\ce{OH}\phantom{.......}
\end{array}\]

b.

\[\begin{array}{cc}
\ce{CH3 - CH2 - CH - CH2 - CH3}\\
|\phantom{.}\\
\phantom{.}\ce{Br}
\end{array}\]

c.

\[\ce{CH3 - CH2 - CH2 - CH2 Br}\]

d.

\[\begin{array}{cc}
\ce{CH3 - CH - CH3 - CH3}\\
|\phantom{.........}\\
\ce{CH3}\phantom{......}
\end{array}\]


Define the following:

Plane polarized light


Define the following:

Chirality


Identify the chiral molecule from the following.


Identify chiral molecule/s from the following.


Identify the chiral molecule from the following.


Identify chiral molecule/s from the following.


Identify the chiral molecule from the following:


Identify the chiral molecule from the following.


Identify the chiral molecule from the following.


Identify chiral molecule/s from the following.


Identify the chiral molecule from the following.


Identify the chiral molecule from the following.


Identify the chiral molecule from the following.


Identify the chiral molecule from the following.


Identify the chiral molecule from the following.


Identify chiral molecule/s from the following.


Identify the chiral molecule from the following.


Identify chiral molecule/s from the following.


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