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प्रश्न
Explain the geometry of [Cu(NH3)4]2+ on the basis of hybridisation [ At. No. Cu = 29 ].
उत्तर
- The oxidation state of Cu in [Cu(NH3)4]2+ is + 2. The electronic configuration of Cu2+ is 3d94s0.
- dsp2 hybridisation of one d, one s and two p orbitals result in square planar geometry.
- Coordinate bonds are formed by overlap of metal dsp2 hybrid orbitals.
- Due to presence of one unpaired electron, [ Cu(NH3)4 ]2+ is paramagnetic. The magnetic moment, μ is 1.73 B.M.
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