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प्रश्न
Why is BiH3 the strongest reducing agent amongst all the hydrides of Group 15 elements?
उत्तर १
As we move down a group, the atomic size increases and the stability of the hydrides of group 15 elements decreases. Since the stability of hydrides decreases on moving from NH3 to BiH3, the reducing character of the hydrides increases on moving from NH3 to BiH3.
उत्तर २
This is because as we move down the group, the size increases, as a result, length of E-H bond increases and its strength decreases, so that the bond can be broken easily to release H2 gas. Hence, BiH3 is the strongest reducing agent.
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संबंधित प्रश्न
Write four points of differences between properties of nitrogen and other elements of group 15.
Arrange the following in the increasing order of property mentioned :
NH3, PH3, AsH3, SbH3, BiH3 (Base strength)
Give reasons When Cl2 reacts with the excess of F2, ClF3 is formed and not FCl3.
Account for the following :
BiH3 is the strongest reducing agent amongst all the hydrides of group 15.
Account for the following :
Sulphur in vapour form exhibits paramagnetic behaviour.
Explain the geometry of [Cu(NH3)4]2+ on the basis of hybridisation [ At. No. Cu = 29 ].
Give a reason for the following:
E° value for (Mn2+|Mn) is negative whereas for (Cu2+|Cu) is positive.
Which of the following element will form acidic oxides of type E2O3?
The ion or group detected by K2[HgI4] is ____________.
Which of the following options are not in accordance with the property mentioned against them?
| (i) | \[\ce{F2 > Cl2 > Br2 > I2}\] | Oxidising power. |
| (ii) | \[\ce{MI > MBr > MC1 > MF}\] | Ionic character of metal halide. |
| (iii) | \[\ce{F2 > Cl2 > Br2 > I2}\] | Bond dissociation enthalpy. |
| (iv) | \[\ce{HI < HBr < HCI < HF}\] | Hydrogen-halogen bond strength. |
Which of the following statements are correct for \[\ce{SO2}\] gas?
(i) It acts as bleaching agent in moist conditions.
(ii) It’s molecule has linear geometry.
(iii) It’s dilute solution is used as disinfectant.
(iv) It can be prepared by the reaction of dilute \[\ce{H2SO4}\] with metal sulphide.
Match the species given in Column I with the shape given in Column II and mark the correct option.
| Column I | Column II |
| (A) \[\ce{SF4}\] | (1) Tetrahedral |
| (B) \[\ce{BrF2}\] | (2) Pyramidal |
| (C) \[\ce{BrO^{-}3}\] | (3) Sea-saw shaped |
| (D) \[\ce{NH^{+}4}\] | (4) Bent T-shaped |
Assertion: N2 is less reactive than P4.
Reason: Nitrogen has more electron gain enthalpy than phosphorus.
Account for the following:
Zinc is a comparatively a soft metal, iron and chromium are typically hard.
The enthalpy change of a reaction does not depends upon?
Basicity of ortho phosphoric acid is:-
The correct order of increase acidic strength of CIOH(1), BrOH (II) and lOH (iii) is.
Which acid of the following pair would you expect to be stronger?
F−CH2−COOH or CH3−COOH
