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प्रश्न
Factorize `x^2 + 12/35 x + 1/35`
उत्तर
Splitting the middle term,
`= x^2 + 5/35 x + 7/35 x + 1/35` `[∵ 12/35 = 5/35 + 7/35 and 5/35 xx 7/35 = 1/35]`
`= x^2 + x/7 + x/5 + 1/35`
`= x(x + 1/7)+ 1/5(x + 1/7)`
`= (x + 1/7)(x + 1/5)`
`∴ x^2 + 12/35 x + 1/35 = (x + 1/7)(x + 1/5)`
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