Advertisements
Advertisements
प्रश्न
Factorize x3 - 2x2 y + 3xy2 - 6y3
उत्तर
Taking x2 common in (x3 - 2x2 y ) and +3y2 common in (3xy2 - 6y3)
= x2 ( x - 2 y ) + 3y2 ( x - 2 y )
= ( x - 2 y)(x2 + 3y2 )
∴ x3 - 2x2 y + 3xy2 - 6y3 = ( x - 2y )(x2 + 3y2 )
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Factorize x (x3 - y3 ) + 3xy ( x - y )
Factorize a2 - b2 + 2bc - c2
Factorize `x^2 + 12/35 x + 1/35`
Factorize `5sqrt5x^2 + 20x + 3sqrt5`
Factorize 2( x + y)2 - 9( x + y) - 5
Factorize the following expressions
64a3 – b3
Factorize 8a3 + 27b3 + 36a2b + 54ab2
Factorize 8a3 – 27b3 – 36a2b + 54ab2
Multiply: (-2x + 3y)(2x - 3y)
Write the coefficient of x2 and x in the following polynomials
`4 + 2/5x^2 - 3x`
